Issue 4629 - Default website boilerplate

gulpfile.js

+/*!
+ * This file is part of website-boilerplate
+ * Copyright (C) 2016 Eyeo GmbH
+ *
+ * website-boilerplate is free software: you can redistribute it and/or
+ * modify it under the terms of the GNU General Public License as published by
+ * the Free Software Foundation, either version 3 of the License, or
+ * (at your option) any later version.
+ *
+ * website-boilerplate is distributed in the hope that it will be useful,
+ * but WITHOUT ANY WARRANTY; without even the implied warranty of
+ * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
+ * GNU General Public License for more details.
+ *
+ * You should have received a copy of the GNU General Public License
+ * along with website-boilerplate.  If not, see <http://www.gnu.org/licenses/>.
+ */
+
+const gulp = require("gulp");
+const sass = require("gulp-sass");
+
+gulp.task("scss", function ()
+{
+  return gulp.src("./static/scss/main.scss")
+    .pipe(sass().on("error", sass.logError))
+    .pipe(gulp.dest("./static/css/"));
+});
+
+gulp.task("watch", function ()
+{
+  gulp.watch("static/scss/*.scss", ["scss"]);

[saroyanm, 2017/01/11 12:04:40]

Getting current error:
Error: watch
/home/saroyanm/projects/abp/websites/website-defaults/boilerplate/static/scss/
ENOSPC

Can you please confirm that you don't get any error running gulp ? 

[ire, 2017/06/22 16:14:24]

I can confirm that I don't get any error running gulp

[ire, 2017/06/22 16:14:24]

This should watch `static/scss/**/*.scss` so that .scss files in sub-directories
will also trigger the task 

Also, is there a reason we are not using the compressed output style option to
minify the output?

[juliandoucette, 2017/06/22 18:23:52]

Acknowledged.

Also, no good reason. Note: If we minify then we need to [include license
headers, a license table, or license magnet links, and source maps] to stay free
and open source and librejs compatible.

+});
+
+gulp.task("build", ["scss"]);
+
+gulp.task("default", ["scss", "watch"]);